8x-28=2x^2+2

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Solution for 8x-28=2x^2+2 equation: 



8x-28=2x^2+2

We move all terms to the left:

8x-28-(2x^2+2)=0

We get rid of parentheses

-2x^2+8x-2-28=0

We add all the numbers together, and all the variables

-2x^2+8x-30=0

a = -2; b = 8; c = -30;
Δ = b2-4ac
Δ = 82-4·(-2)·(-30)
Δ = -176
Delta is less than zero, so there is no solution for the equation

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